The maximum distance between the transmitting and receiving TV towers is $65 \mathrm{~km}$. If the ratio of…

The maximum distance between the transmitting and receiving TV towers is $65 \mathrm{~km}$. If the ratio of the heights of the TV transmitting tower to receiving tower is $36: 49$, the heights of the transmitting and receiving towers respectively are (radius of earth $=6400 \mathrm{~km}$)
  1. 51.2 m, 80 m
  2. 70.3 m, 95.7 m
  3. 30 m, 65 m
  4. 25 m, 75 m

Solution


From Eqs. (i) and (ii), we get and $\begin{aligned} & h_T=70.3 \mathrm{~m} \\ & h_R=95.7 \mathrm{~m} \end{aligned}$

Asked in: AP EAMCET 2018 (22 Apr Shift 2)

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