The maximum amplitude of an amplitude modulated wave is $16 \mathrm{~V}$, while the minimum amplitude is $4 \mathrm{~V}$. The modulation index is

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Aicharya · Accepted Answer

We have, $m=\frac{A_m}{A_c}=\frac{E_{\max }-E_{\min }}{E_{\max }+E_{\min }}$ Here, $E_{\max }=16 \mathrm{~V}$ and $E_{\min }=4 \mathrm{~V}$ $\begin{aligned} & \Rightarrow \quad m=\frac{16-4}{16+4} \ & =\frac{12}{20}=\frac{3}{5}=0.6 \end{aligned}$

The maximum amplitude of an amplitude modulated wave is $16 \mathrm{~V}$, while the minimum amplitude is $4…

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