The maximum amplitude of an AM wave is found to be $20 \mathrm{~V}$ while its minimum amplitude is $4 \mathrm{~V}$. The modulation index is

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Aicharya · Accepted Answer

Maximum amplitude of AM wave,
$A_{\max }=20 \mathrm{~V}$
and minimum amplitude of AM wave,
$A_{\min }=4 \mathrm{~V}$
Modulation index,
$\begin{aligned}
\mu & =\frac{A_{\max }-A_{\min }}{A_{\max }+A_{\min }} \\
& =\frac{20-4}{20+4}=\frac{16}{24}=\frac{2}{3}=0.67
\end{aligned}$

The maximum amplitude of an AM wave is found to be $20 \mathrm{~V}$ while its minimum amplitude is $4…

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