The matrix $A=\left[\begin{array}{ccc}a & -1 & 4 \\ -3 & 0 & 1 \\ -1 & 1 & 2\end{array}\right]$ is not…

The matrix $A=\left[\begin{array}{ccc}a & -1 & 4 \\ -3 & 0 & 1 \\ -1 & 1 & 2\end{array}\right]$ is not invertible only if a =
  1. -17
  2. -16
  3. 16
  4. 17

Solution

Since $\mathrm{A}$ is not invertible, $|\mathrm{A}|=0$ $\begin{aligned} \therefore &\left|\begin{array}{ccc}a & -1 & 4 \\ -3 & 0 & 1 \\ -1 & 1 & 2\end{array}\right|=0 \\ & \mathrm{a}(0-1)-(-1)(-6+1)+4(-3-0)=0 \Rightarrow-\mathrm{a}-5-12=0 \Rightarrow \mathrm{a}=-17 \end{aligned}$

Asked in: MHT CET 2020 (16 Oct Shift 2)

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