The mass of urea required to make $2.5 \mathrm{~kg}$ of 0.25 molal aqueous solution is
- $3.7 \mathrm{~g}$
- $37 \mathrm{~g}$
- $74 \mathrm{~g}$
- $7.4 \mathrm{~g}$
Solution
Asked in: AP EAMCET 2020 (07 Oct Special)
Practice more Some Basic Concepts of Chemistry questions on Aicharya