The mass of the lift is 200 kg , when it ascends with an acceleration of $4 \mathrm{~m} / \mathrm{s}^2$ then…

The mass of the lift is 200 kg , when it ascends with an acceleration of $4 \mathrm{~m} / \mathrm{s}^2$ then the tension in the cable supporting the lift will be [Given: Acceleration due to gravity $\left.g=10 \mathrm{~m} / \mathrm{s}^2\right]$
  1. 800 N
  2. 2800 N
  3. 4200 N
  4. 2000 N

Solution

The equation of motion for the lift is: $\begin{aligned} & \mathrm{T}-\mathrm{ma}=\mathrm{mg} \\ & \mathrm{~T}=\mathrm{m}(\mathrm{~g}+\mathrm{a}) \\ & =200(10+4) \\ & \mathrm{T}=2800 \mathrm{~N} \end{aligned}$

Asked in: MHT CET 2024 (02 May Shift 2)

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