The mass of one mole of a gas is $22.4 \times 10^{-3} \mathrm{~kg}$ and its specific heat ratio is 1.6. The…
The mass of one mole of a gas is $22.4 \times 10^{-3} \mathrm{~kg}$ and its specific heat ratio is 1.6. The speed of sound in the gas at STP is nearly
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Solution
Mass of one mol gas, $\mathrm{m}=22.4 \times 10^{-3} \mathrm{~kg}$
Specific heat ratio, $\mathrm{r}=1.6$
Pressure at STP, $\mathrm{P}=1.01 \times 10^5 \mathrm{~N} / \mathrm{m}^2$
Volume at STP, V $=22.4 \times 10^{-3} \mathrm{~L}$
Speed of sound is given as
$\mathrm{v}=\sqrt{\frac{\gamma \mathrm{P}}{\rho}}=\sqrt{\frac{\gamma \mathrm{PV}}{\mathrm{M}}}$
Substitute necessary values
$\mathrm{v}=\sqrt{\frac{1.6 \times 1.01 \times 10^5 \times 22.4 \times 10^{-3}}{22.4 \times 10^{-3}}}$
$\mathrm{v}=4.02 \times 10^2 \mathrm{~m} / \mathrm{s}$
Asked in: AP EAMCET 2023 (18 May Shift 1)
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