The mass of lift is $2000 \mathrm{~kg}$. When the tension in the supporting cable is $28000 \mathrm{~N}$,…
The mass of lift is $2000 \mathrm{~kg}$. When the tension in the supporting cable is $28000 \mathrm{~N}$, then its acceleration is :
- $14 \mathrm{~ms}^{-2}$ upwards
- $30 \mathrm{~ms}^{-2}$ downwards
- $4 \mathrm{~ms}^{-2}$ upwards
- $4 \mathrm{~ms}^{-2}$ downwards
Solution
$\begin{aligned}
& \Sigma F=m a \\
& \Rightarrow \mathrm{T}-\mathrm{mg}=\mathrm{ma} \\
& \mathrm{a}=\frac{\mathrm{T}-\mathrm{mg}}{\mathrm{m}}=4 \mathrm{~m} / \mathrm{s}^2
\end{aligned}$
Asked in: NEET 2009 (Mains)
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