The mass defect in a particular reaction is 0 . 4 g . The amount of energy liberated is n × 10 7 kW h ,…

The mass defect in a particular reaction is 0.4 g. The amount of energy liberated is n×107 kW h, where n= _____. (speed of light =3×108 m s-1)

Solution

Energy liberated is given by, E=mc2

=0.4×10-3×3×1082

=3600×107 kW s

=3600×1073600 kW h=1×107 kW h

Asked in: JEE Main 2024 (31 Jan Shift 1)

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