The major product obtained in the following reaction is,

The major product obtained in the following reaction is,

$C_{6} H_{5} CH = {CHC}_{6} H_{5}$
$(+) C_{6} H_{5} CH (OtBu) {CH}_{2} C_{6} H_{5}$
$(-) C_{6} H_{5} CH (OtBu) {CH}_{2} C_{6} H_{5}$
$(\pm) C_{6} H_{5} CH (OtBu) {CH}_{2} C_{6} H_{5}$

Solution

Tert-butyl oxide is a strong base and a weak nucleophile.

In presence of a strong base and heat, elimination reaction favours over substitution reaction.

The type of elimination taking place here is $β$ -elimination

So, option A is the correct answer.

Asked in: JEE Main 2017 (02 Apr)

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