The major product ′ Y ′ in the following reaction is:

The major product $\mathrm{\prime }\mathrm{Y}\mathrm{\prime }$ in the following reaction is:

Solution

In the first step, elimination reaction takes place as sodium ethoxide is a strong base



in the second step, hydrobromination takes place in accordance with Markovnikov's rule

Asked in: JEE Main 2019 (10 Apr Shift 2)

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