The major product formed in the following reaction is : CH 2 CH = CHCH CH 3 2 → HBr

1. ${\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{CH}\left(\mathrm{Br}\right)\mathrm{CH}{\left({\mathrm{CH}}_3\right)}_2$
2. ${\mathrm{CH}}_3\mathrm{CH}\left(\mathrm{Br}\right){\mathrm{CH}}_2\mathrm{CH}{\left({\mathrm{CH}}_3\right)}_2$
3. $\mathrm{Br}{\left({\mathrm{CH}}_2\right)}_3\mathrm{CH}{\left({\mathrm{CH}}_3\right)}_2$
4. ${\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{CH}}_2\mathrm{C}\left(\mathrm{Br}\right){\left({\mathrm{CH}}_3\right)}_2$

Asked in: JEE Main 2020 (05 Sep Shift 2)

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