The major product $\mathrm{P}$ in the following reaction is $\left(\mathrm{CH}_{3}ight)_{3}…

The major product $\mathrm{P}$ in the following reaction is
$\left(\mathrm{CH}_{3}ight)_{3} \mathrm{COH}+\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH} \stackrel{\mathrm{H}^{+}}{\longrightarrow} \mathrm{P}$
  1. $\left(\mathrm{CH}_{3}ight)_{3} \mathrm{COC}\left(\mathrm{CH}_{3}ight)_{3}$
  2. $\left(\mathrm{CH}_{3}ight)_{3} \mathrm{COC}_{2} \mathrm{H}_{5}$
  3. $\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OC}_{2} \mathrm{H}_{5}$
  4. $\left(\mathrm{CH}_{3}ight)_{2} \mathrm{C}=\mathrm{CH}_{2}$

Solution

tert - Butyl alcohol is preferentially protonated because its corresponding carbocation is highly stable than that of $\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}$


The tert-butyl cation is preferentially attacked by $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}$ rather than bulky $\left(\mathrm{CH}_{3}ight)_{3} \mathrm{COH}$

Asked in: JEE-TOPICTESTS-CHEMISTRY

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