The major compound from which iodine is isolated is
- $\mathrm{NaI}$
- $\mathrm{NaIO}_{3}$
- $\mathrm{NaIO}_{4}$
- $\mathrm{I}_{2} \mathrm{O}_5$
Solution
$\mathrm{NaIO}_3+\mathrm{H}_2 \mathrm{SO}_4 ightarrow \mathrm{NaHSO}_4+\mathrm{HIO}_3, \mathrm{HIO}_3+5 \mathrm{HI} ightarrow 3 \mathrm{H}_2 \mathrm{O}+3 \mathrm{I}_2$ .
Asked in: JEE-TOPICTESTS-CHEMISTRY
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