The magnitude of the projection of the vector $\mathbf{a}=4 \mathbf{i}-3 \mathbf{j}+2 \mathbf{k}$ on the…

The magnitude of the projection of the vector $\mathbf{a}=4 \mathbf{i}-3 \mathbf{j}+2 \mathbf{k}$ on the line which makes equal angles with the coordinate axes is
  1. $\sqrt{2}$
  2. $\sqrt{3}$
  3. $\frac{1}{\sqrt{3}}$
  4. $\frac{1}{\sqrt{2}}$

Solution

Let the vector $\mathbf{v}$ make an angle $\alpha$ with each of the three axes, then direction cosine of $\mathbf{v}$ are $ < \cos \alpha, \cos \alpha, \cos \alpha>$ Also, $\quad \cos ^2 \alpha+\cos ^2 \alpha+\cos ^2 \alpha=1$ Hence, direction cosine of $\mathbf{v}$ are $ < \frac{1}{\sqrt{3}}, \frac{1}{\sqrt{3}}, \frac{1}{\sqrt{3}}>$ or $ < -\frac{1}{\sqrt{3}},-\frac{1}{\sqrt{3}},-\frac{1}{\sqrt{3}}>$ So, the required line which makes equal angle with the coordinate axes is $\mathbf{v}= \pm \frac{1}{\sqrt{3}} \mathbf{i} \pm \frac{1}{\sqrt{3}} \mathbf{j} \pm \frac{1}{\sqrt{3}} \mathbf{k}$ Now, the magnitude of the projection of the vector $\mathbf{a}=4 \mathbf{i}-3 \mathbf{j}+2 \mathbf{j}$ on line $\mathbf{v}$. $\therefore$ Projection of a along r $\begin{aligned} \mathbf{v} & =\frac{\mathbf{a} \cdot \mathbf{v}}{|\mathbf{v}|} \\ & =\frac{3 / \sqrt{3}}{1}=\sqrt{3} \end{aligned}$

Asked in: AP EAMCET 2011

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