The magnitude of the projection of the vector $2 \hat{i}+3 \hat{j}+\hat{k}$ on the vector perpendicular to…

The magnitude of the projection of the vector $2 \hat{i}+3 \hat{j}+\hat{k}$ on the vector perpendicular to the plane containing the vectors $\hat{i}+\hat{j}+\hat{k}$ and $\hat{i}+2 \hat{j}+3 \hat{k}$ is
  1. $\sqrt{\frac{3}{2}}$ units
  2. $\frac{\sqrt{3}}{2}$ units
  3. $\frac{3}{\sqrt{2}}$ units
  4. $3 \sqrt{6}$ units

Solution

$\begin{aligned} & \frac{|(2 \hat{i}+3 \hat{j}+\hat{k}) \cdot\{(\hat{i}+\hat{j}+\hat{k}) \times(\hat{i}+2 \hat{j}+3 \hat{k})\}|}{|(\hat{i}+\hat{j}+\hat{k}) \times(\hat{i}+2 \hat{j}+3 \hat{k})|} \\ & =\frac{|(2 \hat{i}+3 \hat{j}+\hat{k}) \cdot(\hat{i}-2 \hat{j}+\hat{k})|}{|\hat{i}+\hat{j}+\hat{k}|} \\ & =\frac{|2-6+1|}{\sqrt{1^2+(-2)^2+1^2}}=\frac{3}{\sqrt{6}}=\sqrt{\frac{3}{2}}\end{aligned}$

Asked in: MHT CET 2022 (06 Aug Shift 2)

Practice more Three Dimensional Geometry questions on Aicharya