
The magnitude of heat exchanged by a system for the given cyclic process ABCA (as shown in figure) is (in SI…

- $5 \pi$
- $40 \pi$
- $10 \pi$
- zero
Solution

$\begin{aligned} & \mathrm{W}=\frac{1}{2} \pi \mathrm{R}^2 \\ & =\frac{1}{2} \times \pi \times\left(\frac{200}{2} \times 10^3\right) \times \frac{200}{2} \times 10^{-6} \\ & =\frac{10 \pi}{2}=5 \pi \mathrm{~J}\end{aligned}$
Asked in: JEE Main 2025 (24 Jan Shift 2)