The magnetic susceptibility of a material of a rod is 349 and permeability of vacuum $\mu_0$ is $4 \pi…
The magnetic susceptibility of a material of a rod is 349 and permeability of vacuum $\mu_0$ is $4 \pi \times 10^{-7} \mathrm{SI}$ units. Absolute permeability of the material of the rod in SI units
$4200 \times 10^{-7}$
$4600 \times 10^{-7}$
$4400 \times 10^{-7}$
$4800 \times 10^{-7}$
Solution
Given: $\mu_0=4 \pi \times 10^{-7} \mathrm{Hm}^{-1}$
Magnetic susceptibility of a material of rod: $\chi_{\mathrm{m}}=349$
$\therefore$ absolute permeability of material of rod:
$\mu=\mu_0\left(1+\chi_{\mathrm{m}}\right)$
Or,
$\mu=4 \pi \times 10^{-7}(1+349)=43982.3 \times 10^{-4} \mathrm{Hm}^{-1} \approx 4400 \times 10^{-7} \mathrm{Hm}^{-1}$