The magnetic potential energy, when a magnetic bar of magnetic moment $\vec{m}$ is placed perpendicular to…

The magnetic potential energy, when a magnetic bar of magnetic moment $\vec{m}$ is placed perpendicular to the magnetic field $\vec{B}$ is
  1. $-\frac{m B}{2}$
  2. Zero
  3. $-m B$
  4. $m B$

Solution

Potential energy stored in external magnetic field is given by $U=-\vec{m} \cdot \vec{B}$ $\because$ Angle between $\vec{m}$ and $\vec{B}$ is $90^{\circ}$ $\therefore \quad U=-m B \cos 90^{\circ}$ $=0$ :

Asked in: NEET 2024 (Re-NEET)

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