The magnetic potential energy stored in certain inductor is $64 \times 10^{-3} \mathrm{~J}$, when the…

The magnetic potential energy stored in certain inductor is $64 \times 10^{-3} \mathrm{~J}$, when the current in the inductor is 80 mA . This inductor is of inductance
  1. 0.20 H
  2. 2.0 H
  3. 20 H
  4. 200 H

Solution

Energy stored in inductor, $\mathrm{E}=\frac{1}{2} \mathrm{LI}^2$ $\therefore \quad L=\frac{2 \mathrm{E}}{\mathrm{I}^2}=\frac{2 \times 64 \times 10^{-3}}{\left(80 \times 10^{-3}\right)^2}=20 \mathrm{H}$

Asked in: MHT CET 2024 (09 May Shift 2)

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