The magnetic moment is measured in Bohr Magneton (BM). Spin only magnetic moment of Fe in Fe H 2 O 6 3 + and Fe CN 6 3 - complexes respectively is:

Question

Aicharya · Accepted Answer

The spin only magnetic moment can be calculated as follows

$μ = \sqrt{n (n + 2)} BM$

$n =$ Number of unpaired electrons

${[Fe {(H_{2} O)}_{6}]}^{3 +} = d^{5} (High spin complex) = 5$ .unpaired electrons
$μ = \sqrt{5 \times 7} = \sqrt{35}$
$= 5.92 B . M .$
${[Fe {(CN)}_{6}]}^{3 +} = d^{5} (Low spin complex) = 1$
$μ = \sqrt{1 \times 3} = \sqrt{3}$
$= 1.732 B . M .$

The magnetic moment is measured in Bohr Magneton (BM). Spin only magnetic moment of Fe in Fe H 2 O 6 3 + and…

Solution