The magnetic induction at the centre of a current carrying circular coil of radius $8 \mathrm{~cm}$ is $6…

The magnetic induction at the centre of a current carrying circular coil of radius $8 \mathrm{~cm}$ is $6 \sqrt{6}$ times the magnetic induction at a point on its axis. Then the distance of the point from the centre of the coil in $\mathrm{cm}$ is $(\sqrt{5}=2.236)$
  1. $17.89$
  2. $1.789$
  3. $178.9$
  4. $0.1789$

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2017 (25 Apr Shift 2)

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