The magnetic flux through a coil of resistance 'R' changes by an amount ' $\Delta \phi$ 'in time ' $\Delta…

The magnetic flux through a coil of resistance 'R' changes by an amount ' $\Delta \phi$ 'in time ' $\Delta t$ '. The amount of induced current and induced charge in the coil are respectively
  1. $\left(\frac{\Delta \phi}{\Delta t}\right) \mathrm{R}$ and $\frac{\mathrm{R}}{\Delta \phi}$
  2. $\frac{\Delta \phi}{\mathrm{R}}$ and $\mathrm{R}\left(\frac{\Delta \mathrm{t}}{\Delta \phi}\right)$
  3. $\frac{\Delta \phi}{\mathrm{R}}+\mathrm{R}$ and $\frac{\Delta \phi}{\Delta \mathrm{t}}$
  4. $\left(\frac{\Delta \phi}{\Delta \mathrm{t}}\right) \times \frac{1}{\mathrm{R}}$ and $\frac{\Delta \phi}{\mathrm{R}}$

Solution

According to Faraday's law of electromagnetic induction, $\begin{aligned} & |e|=\frac{\Delta \phi}{\Delta t} \\ & I R=\frac{\Delta \phi}{\Delta t} \\ & I=\left(\frac{\Delta \phi}{\Delta t}\right) \frac{1}{R} \end{aligned}$ $\therefore \quad$ The total quantity of electric charge passing through the circuit is $\begin{aligned} \mathrm{Q} & =\mathrm{I} \times \Delta \mathrm{t} \\ & =\frac{\Delta \phi}{\mathrm{R}} \end{aligned}$

Asked in: MHT CET 2024 (09 May Shift 1)

Practice more Electromagnetic Induction questions on Aicharya