The magnetic flux near the axis and inside the air core solenoid of length 80 cm carrying current ' I ' is $1.57 imes 10^{-6} \mathrm{~Wb}$. Its magnetic moment will be [cross-sectional area of a solenoid is very small as compared to its length,$\mu_0=4 \pi imes 10^{-7} ext { SI unit]…

Question

The magnetic flux near the axis and inside the air core solenoid of length 80 cm carrying current ' I ' is $1.57 	imes 10^{-6} \mathrm{~Wb}$. Its magnetic moment will be [cross-sectional area of a solenoid is very small as compared to its length,$\mu_0=4 \pi 	imes 10^{-7} 	ext { SI unit] }(\pi=3.14)$

Aicharya · Accepted Answer

The magnetic induction inside the solenoid, $B=\frac{\mu_0 \mathrm{NI}}{L}$
Magnetic flux, $\phi=\mathrm{BA}=\frac{\mu_0 \mathrm{NIA}}{\mathrm{~L}}$ $\begin{aligned} \text { Magnetic moment } & =\mathrm{NIA}=\frac{\phi \mathrm{L}}{\mu_0} \\ & =\frac{\left(1.57 \times 10^{-6}\right) \times 0.8}{4 \pi \times 10^{-7}} \\ & =1 \mathrm{Am}^2\end{aligned}$ ^

The magnetic flux near the axis and inside the air core solenoid of length 80 cm carrying current ' I ' is…

Solution