The magnetic field of a given length of wire for a single turn coil at the centre is ' $B$ ' then, its value for two turns coil for the same wire is:

Question

Aicharya · Accepted Answer

Here $B_1=B=\frac{\mu_0 I}{2 R}$ $\begin{aligned} & B_2=\frac{\mu_0(2 \mathrm{I})}{2 r} \ & 	herefore 2 	imes 2 \pi r=2 \pi R \Rightarrow r=R / 2 \end{aligned}$ So, $B_2 = 4 B$

The magnetic field of a given length of wire for a single turn coil at the centre is ' $B$ ' then, its value…

Solution