The magnetic energy' stored in an inductor of inductance $5 \mu \mathrm{H}$ carrying a current of 2 A is

The magnetic energy' stored in an inductor of inductance $5 \mu \mathrm{H}$ carrying a current of 2 A is
  1. 10 mJ
  2. 5 mJ
  3. $10 \mu \mathrm{~J}$
  4. $5 \mu \mathrm{~J}$

Solution

$\mathrm{U}=\frac{1}{2} \mathrm{LI}^2=\frac{1}{2} \times\left(5 \times 10^{-6}\right) \times 2^2=10 \mu \mathrm{~J}$ .

Asked in: MHT CET 2024 (02 May Shift 1)

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