The longest rod that can be placed inside a cubical box of edge $10$ cm has length:
The longest rod that can be placed inside a cubical box of edge $10$ cm has length:
- $10$ cm
- $10\sqrt{2}$ cm
- $10\sqrt{3}$ cm
- $30$ cm
Solution
Longest rod = space diagonal of the cube $= a\sqrt{3} = 10\sqrt{3}$ cm.
Asked in: IMO
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