The logical statement $(\mathrm{p} \rightarrow \mathrm{q}) \wedge(\mathrm{p} \rightarrow \sim \mathrm{p})$ is equivalent to

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Aicharya · Accepted Answer

$\begin{aligned} & (\mathrm{p} ightarrow \mathrm{q}) \wedge(\mathrm{q} ightarrow \sim \mathrm{p}) \ & \equiv(\sim \mathrm{p} \vee \mathrm{q}) \wedge(\sim \mathrm{q} \vee \sim \mathrm{p}) \ & =(\sim \mathrm{p}) \vee(\mathrm{q} \wedge-\mathrm{q}) \ & \equiv(\sim \mathrm{p}) \vee \mathrm{F} \equiv \sim \mathrm{p}\end{aligned}$

The logical statement $(\mathrm{p} \rightarrow \mathrm{q}) \wedge(\mathrm{p} \rightarrow \sim \mathrm{p})$…

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