The logical expression $[p \wedge(q \vee r)] \vee[\sim r \wedge \sim q \wedge p]$ is equivalent to
The logical expression $[p \wedge(q \vee r)] \vee[\sim r \wedge \sim q \wedge p]$ is equivalent to
- $\mathrm{q}$
- $\sim q$
- $\sim \mathrm{p}$
- $\mathrm{p}$
Solution
$[p \wedge(q \vee r)] \vee[\sim r \wedge \sim \wedge \wedge p]$
$\equiv[p \wedge(q \vee r)] \vee[p \wedge(\sim q \wedge \sim r)]$
$\underline{\underline{\underline{\alpha}}}[p \wedge(q \vee r)] \vee[p \wedge(\sim(q \vee r))]$
$=p \wedge[(q \vee r) \vee(\sim(q \vee r))]$
$=p \wedge T=p$
Asked in: MHT CET 2020 (14 Oct Shift 1)
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