The locus of the point whose ratio of distance from the origin to its distance from \((-2,-3)\) is \(5: 7\),…

The locus of the point whose ratio of distance from the origin to its distance from \((-2,-3)\) is \(5: 7\), is given by.........
  1. \(24\left(x^2+y^2\right)-100 x-150 y-325=0\)
  2. \(24\left(x^2+y^2\right)+100 x+150 y-325=0\)
  3. \(24\left(x^2+y^2\right)-100 x+150 y+325=0\)
  4. \(2 x^2+2 y^2=325\)

Solution

Let the point \(P(x, y)\), such that \(O P: A P=5: 7\), where \(O\) is the origin and \(A(-2,-3)\), so \(\begin{aligned} & \frac{\sqrt{x^2+y^2}}{\sqrt{(x+2)^2+(y+3)^2}}=\frac{5}{7} \\ \Rightarrow \quad & 49\left(x^2+y^2\right)=25\left[x^2+y^2+4 x+6 y+13\right] \\ \Rightarrow \quad & 24\left(x^2+y^2\right)-100 x-150 y-375=0 \end{aligned}\) Hence, option (a) is correct.

Asked in: AP EAMCET 2020 (21 Sep Shift 1)

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