The locus of the point of intersection of perpendicular tangents drawn to the circle $x^2+y^2=10$ is
The locus of the point of intersection of perpendicular tangents drawn to the circle $x^2+y^2=10$ is
$x^2+y^2=5$
$x^2+y^2=20$
$x^2+y^2=25$
$x^2+y^2=100$
Solution
Locus of points of intersection of perpendicular tangents is the director circle. Given circle is $x^2+y^2=10$. $\therefore$ Director circle is $x^2+y^2=20$ is the required locus.