The load resistance and the base-emitter voltage of a transistor in CE configuration are $5 \mathrm{k}…
The load resistance and the base-emitter voltage of a transistor in CE configuration are $5 \mathrm{k} \Omega$ and $0.02 \mathrm{~V}$ respectively. If the collector current is $2 \mathrm{~mA}$, then its voltage gain is
$1000$
$500$
$1500$
$50$
Solution
$\mathrm{I}_{\mathrm{C}}=2 \times 10^{-3} \mathrm{~A}$
Voltage gain, $A_v=\frac{V_{C E}}{V_{B E}}=\frac{I_c R_c}{V_{B E}}$ $=\frac{2 \times 10^{-3} \times 5 \times 10^3}{.02}=500$