The lines represented by the equation $x^2-y^2-x+3 y-2=0$ are :
The lines represented by the equation $x^2-y^2-x+3 y-2=0$ are :
$x+y-1=0, x-y+2=0$
$x-y-2=0, x+y+1=0$
$x+y+2=0, x-y-1=0$
$x-y+1=0, x+y-2=0$
Solution
The equation of pair of straight lines is $x^2-y^2-x+3 y-2=0$
This equation can be rewritten as
$(x-y+1)(x+y-2)=0$
$\therefore$ The equation of lines which are represented by the given equation, are
$x-y+1=0 \text { and } x+y-2=0 .$