The length of the tangent drawn from any point on the circle \(x^2+y^2+2 g x+2 f y+c_1=0\) to the circle…
- \(\sqrt{C_2-c_1}\)
- \(\sqrt{c_1^2+c_2^2}\)
- \(c_1+c_2\)
- \(c_1-c_2\)
Solution

Clearly, length of tangent is \(\begin{aligned} A T & =\sqrt{A O^2-O T^2}=\sqrt{r_1^2-r_2^2} \\ & =\sqrt{\left(g^2+f^2-c_1\right)-\left(g^2+f^2-c_2\right)}=\sqrt{c_2-c_1} \end{aligned}\)
Asked in: AP EAMCET 2020 (17 Sep Shift 2)