The length of the perpendicular from the origin to the plane $\bar{r}$. $(3 \hat{i}-4 \hat{j}+12 \hat{k})=8$…
The length of the perpendicular from the origin to the plane $\bar{r}$. $(3 \hat{i}-4 \hat{j}+12 \hat{k})=8$ is
- 8 units
- $\frac{13}{8}$
- $\frac{8}{13}$
- 13 units
Solution
The required length of perpendicular $=\frac{8}{\sqrt{3^2+(-4)^2+12^2}}=\frac{8}{13}$
Asked in: MHT CET 2022 (07 Aug Shift 2)
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