The length of the normal to the curve $x=a(\theta+\sin \theta), y=a(1-\cos \theta)$ at…
The length of the normal to the curve $x=a(\theta+\sin \theta), y=a(1-\cos \theta)$ at $\theta=\frac{\pi}{2}$ is
- $a^2$
- $a \sqrt{2}$
- $2 a$
- $a$
Solution
No solution. Refer to answer key.
Asked in: AP EAMCET 2017 (24 Apr Shift 2)
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