The length of the diameter of the circle \(x^2+y^2-6 x-8 y=0\) is units

The length of the diameter of the circle \(x^2+y^2-6 x-8 y=0\) is units
  1. 5
  2. 10
  3. 15
  4. 20

Solution

Cirle is \(x^2+y^2-6 x-8 y=0\) Radius of circle is, \(r=\sqrt{g^2+f^2-c}=\sqrt{3^2+4^2-0}=5 \text { units }\) Diameter \(=2 r=10\) units

Asked in: AP EAMCET 2020 (17 Sep Shift 2)

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