The length of latusrectum of parabola $y^2+8 x-2 y+17=0$ is
The length of latusrectum of parabola $y^2+8 x-2 y+17=0$ is
$2$
$4$
$8$
$16$
Solution
The given equation of the parabola is
$\Rightarrow \quad \begin{array}{ll} & y^3+8 x-2 y+17=0 \\ \Rightarrow \quad & (y-1)^2+8 x+16=0 \\ & (y-1)^2=-8(x+2)\end{array}$
Length of the latusrectum $=4 a=8$