The length of latus rectum of the parabola whose focus is at $(1,-2)$ and directrix is the line $x+y+3=0$ is
The length of latus rectum of the parabola whose focus is at $(1,-2)$ and directrix is
the line $x+y+3=0$ is
- $8 \sqrt{2}$ units
- $2 \sqrt{2}$ units
- $\sqrt{2}$ units
- $4 \sqrt{2}$ units
Solution
$\hat{f}^{(1,-2)}$
$x+y+3=0$
Distance of focus from
$\text { Dizectrix }=22$
$\begin{array}{l}
1^{2} \text { distance } \\
=\frac{|1-2+3|}{\sqrt{2}} \\
=\sqrt{2} .
\end{array}$
Length of L.R
$=2 \sqrt{2}$
Asked in: MHT CET 2020 (13 Oct Shift 1)
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