The length of latus rectum of the parabola whose focus is at $(1,-2)$ and directrix is the line $x+y+3=0$ is

The length of latus rectum of the parabola whose focus is at $(1,-2)$ and directrix is the line $x+y+3=0$ is
  1. $8 \sqrt{2}$ units
  2. $2 \sqrt{2}$ units
  3. $\sqrt{2}$ units
  4. $4 \sqrt{2}$ units

Solution

$\hat{f}^{(1,-2)}$ $x+y+3=0$ Distance of focus from $\text { Dizectrix }=22$ $\begin{array}{l} 1^{2} \text { distance } \\ =\frac{|1-2+3|}{\sqrt{2}} \\ =\sqrt{2} . \end{array}$ Length of L.R $=2 \sqrt{2}$

Asked in: MHT CET 2020 (13 Oct Shift 1)

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