The length of each side of a rhombus with diagonals $16$ cm and $12$ cm is:

The length of each side of a rhombus with diagonals $16$ cm and $12$ cm is:
  1. $8$ cm
  2. $10$ cm
  3. $12$ cm
  4. $14$ cm

Solution

Diagonals bisect each other at right angles, forming right triangles with legs $8$ cm and $6$ cm. Side $= \sqrt{8^{2}+6^{2}} = \sqrt{100} = 10$ cm.

Asked in: IMO

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