The least coefficient of friction for an inclined plane inclined at angle $\alpha$ with horizontal in order…

The least coefficient of friction for an inclined plane inclined at angle $\alpha$ with horizontal in order that a solid cylinder will roll down without slipping is
  1. \(\frac{2}{3} \tan \alpha\)
  2. \(\frac{2}{7} \tan \alpha\)
  3. \(\frac{1}{3} \tan \alpha\)
  4. \(\frac{4}{3} \tan \alpha\)

Solution

\(\mu_{\min }=\frac{\tan \alpha}{1+\frac{\mathrm{mR}^2}{\mathrm{I}}}=\frac{\tan \alpha}{1+2}=\frac{1}{3} \tan \alpha\) as \(I=\frac{1}{2} \mathrm{mR}^2\) .

Asked in: JEE Mains - Rotational Motion - Test 3

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