The largest $\mathrm{n} \in \mathrm{N}$ such that $3^{\mathrm{n}}$ divides 50 ! is:

The largest $\mathrm{n} \in \mathrm{N}$ such that $3^{\mathrm{n}}$ divides 50 ! is:
  1. 21
  2. 22
  3. 20
  4. 23

Solution

$2^\alpha \cdot 3^\beta \cdot 5^\gamma$
$\mathrm{B}=\left[\frac{50}{3}\right]+\left[\frac{50}{3^2}\right]+\left[\frac{50}{3^3}\right]+\left[\frac{50}{3^4}\right]$
$=16+5+1=22$
Maximum value of $n$ is 22 /

Asked in: JEE Main 2025 (02 Apr Shift 1)

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