The largest number of molecules is in
- $36 \mathrm{~g}$ of water
- $28 \mathrm{~g}$ of carbon monoxide
- $46 \mathrm{~g}$ of ethyl alcohol
- $54 \mathrm{~g}$ of nitrogen pentoxide
Solution
$=\frac{36}{18} \times 6.023 \times 10^{23}=2 \times 6.023 \times 10^{23}$
Number of molecules in $28 \mathrm{~g}$ of $\mathrm{CO}$
$=\frac{28}{28} \times 6.023 \times 10^{23} \quad=1 \times 6.023 \times 10^{23}$
Number of molecules in $46 \mathrm{~g}$ of $\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}$
$=\frac{46}{46} \times 6.023 \times 10^{23}=1 \times 6.023 \times 10^{23}$
Number of molecules in $54 \mathrm{~g}$ of $\mathrm{N}_{2} \mathrm{O}_{5}$
$=\frac{54}{108} \times 6.023 \times 10^{23}=0.5 \times 6.023 \times 10^{23}$
Hence, in these $36 \mathrm{~g}$ of water has largest number of molecules. *
Asked in: JEE-TOPICTESTS-CHEMISTRY
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