The largest among the distances from the point $P(15,9)$ to the points on the circle $x^2+y^2-6 x-8 y-11=0$ is

Question

Aicharya · Accepted Answer

$x^2+y^2-6 x-8 y-11=0, P(15,9)$ Centre $(C)=(3,4)$ $	ext { Radius }=\sqrt{9+16+11}=6 ; C P=\sqrt{(15-3)^2+(9-4)^2}=13$ $	herefore$ Greatest distance $=13+6=19$

The largest among the distances from the point $P(15,9)$ to the points on the circle $x^2+y^2-6 x-8 y-11=0$ is

Solution