The kinetic energy of an electron in the second Bohr orbit of a hydrogen atom is equal to $\frac{h^{2}}{x {ma}_{0}^{2}} .$ The value of $10 x$ is ( $a_{0}$ is radius of Bohr's orbit)
(Nearest integer)
[Given: $π = 3.14$ ]

Question

The kinetic energy of an electron in the second Bohr orbit of a hydrogen atom is equal to $\frac{h^{2}}{x {ma}_{0}^{2}} .$ The value of $10 x$ is ( $a_{0}$ is radius of Bohr's orbit)

(Nearest integer)

[Given: $π = 3.14$ ]

Aicharya · Accepted Answer

x = 8 &#960; 2 &#215; 16 4 = 32 &#960; 2 = 32 ( 3 . 14 ) 2 = 315 . 5072 10 x = 315 . 5072

The kinetic energy of an electron in the second Bohr orbit of a hydrogen atom is equal to h 2 x   ma 0…

Solution

The kinetic energy of an electron in the second Bohr orbit of a hydrogen atom is equal to h 2 x &#160; ma 0…

Solution

The kinetic energy of an electron in the second Bohr orbit of a hydrogen atom is equal to h 2 x ma 0…