The kinetic energy of a particle moving along a circle of radius ' $R$ ' depends on the distance '…

The kinetic energy of a particle moving along a circle of radius ' $R$ ' depends on the distance ' $\mathrm{s}$ ' as $\mathrm{K}=\mathrm{as}^2$ where ' $\mathrm{a}$ ' is a constant. Then the force acting on the particle is
  1. $\frac{2 \mathrm{as}^2}{\mathrm{R}}$
  2. $2 \mathrm{as}\left[1+\frac{\mathrm{s}^2}{\mathrm{R}^2}\right]^{1 / 2}$
  3. $2 \mathrm{as}$
  4. $2 \mathrm{a}\left(\frac{\mathrm{R}}{\mathrm{s}}\right)^{1 / 2}$

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2017 (24 Apr Shift 2)

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