The kinetic energy needed to project a body of mass $m$ from the earth surface (radius $R$ ) to infinity is
The kinetic energy needed to project a body of mass $m$ from the earth surface (radius $R$ ) to infinity is
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$\mathrm{mgR} / 2$
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$2 \mathrm{mgR}$
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$\mathrm{mgR}$
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$\mathrm{mgR} / 4$
Solution
$\mathrm{KE}=\frac{1}{2} \mathrm{mv}_{\mathrm{esc}}^2=\frac{1}{2} \mathrm{~m}(\sqrt{2 \mathrm{gR}})^2=\mathrm{mgR}$
Asked in: JEE Main 2002
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