The K α X-ray of molybdenum has wavelength 0 . 071   nm . If the energy of a molybdenum atom with a K electron knocked out is 27 . 5   keV , the energy of this atom when an L electron is knocked out will be keV . (Round off to the nearest integer ) h = 4 . 14 × 10 - 15  …

Question

The K &#945; X-ray of molybdenum has wavelength 0 . 071 &#160; nm . If the energy of a molybdenum atom with a K electron knocked out is 27 . 5 &#160; keV , the energy of this atom when an L electron is knocked out will be keV . (Round off to the nearest integer ) h = 4 . 14 &#215; 10 - 15 &#160; eV &#160; s , &#160; c = 3 &#215; 10 8 &#160; m &#160; s - 1

Aicharya · Accepted Answer

E k &#945; = E k - E L h c &#955; k &#945; = E k - E L E L = E k - h c &#955; k &#945; = 27 . 5 &#160; KeV - 12 . 42 &#215; 10 - 7 eV &#160; m 0 . 071 &#215; 10 - 9 &#160; m E L = ( 27 . 5 - 17 . 5 ) &#160; keV = 10 &#160; keV

The K α X-ray of molybdenum has wavelength 0 . 071   nm . If the energy of a molybdenum atom with…

Solution

The K &#945; X-ray of molybdenum has wavelength 0 . 071 &#160; nm . If the energy of a molybdenum atom with…

Solution

The K α X-ray of molybdenum has wavelength 0 . 071 nm . If the energy of a molybdenum atom with…