The joint equation of pair of lines through the origin and making an equilateral triangle with the line…
- $3 x^2-y^2=0$
- $5 x^2-y^2=0$
- $x^2-3 y^2=0$
- $\sqrt{3} x^2-y^2=0$
Solution
$\begin{aligned} & y=\tan 60^{\circ} x \Rightarrow y=x \\ & y=\tan 120^{\circ} x \Rightarrow y=-x \\ & \text { joint equation }=(x-y)(x+y)=0 \\ & \Rightarrow 3 x^2-y^2=0\end{aligned}$Asked in: MHT CET 2022 (06 Aug Shift 2)