The IUPAC name of $\left[\mathrm{Pt}\left(\mathrm{NH}_{3}ight)_{4}\left(\mathrm{NO}_{2}ight)…

The IUPAC name of $\left[\mathrm{Pt}\left(\mathrm{NH}_{3}ight)_{4}\left(\mathrm{NO}_{2}ight) \mathrm{Cl}ight] \mathrm{SO}_{4}$ is
  1. tetramminechloronitroplatinum(II) sulphate
  2. tetramminechloronitroplatinum(IV) sulphate
  3. chlorotetramminenitroplatinum(IV) sulphate
  4. chloronitrotetrammineplatinum(IV) sulphate

Solution

Given the compound, $\left[\mathrm{Pt}\left(\mathrm{NH}_{3}ight)_{4}\left(\mathrm{NO}_{2}ight) \mathrm{Cl}ight] \mathrm{SO}_{4}$.
Here, we know $\mathrm{SO}_{4}$ has $-2$ charge.
So, the overall charge on $[\left.\mathrm{Pt}\left(\mathrm{NH}_{3}ight)_{4}\left(\mathrm{NO}_{2}ight) \mathrm{Cl}ight]$ is $+2 . \mathrm{Cl}$ and $\mathrm{NO}_{2}$ has $-1$ valency each.
Therefore, charge on $\mathrm{Pt}$ has to be $+4$ to balance the overall charge.
Therefore, the IUPAC name of $\left[\mathrm{Pt}\left(\mathrm{NH}_{3}ight)_{4}\left(\mathrm{NO}_{2}ight) \mathrm{Cl}ight] \mathrm{SO}_{4}$ is tetramminechloronitroplatinum $\mathrm{(IV)}$ sulphate.

Asked in: JEE-TOPICTESTS-CHEMISTRY

Practice more COORDINATION COMPOUNDS questions on Aicharya